A tabletop gamer has designed a game that requires three dice to be thrown onto

Question

A tabletop gamer has designed a game that requires three dice to be thrown onto a tray with a measurement grid. To add an extra degree of randomness, the coordinates of the center of mass of the three dice are used as well. The mases of the three dice are 11.9 g, 14.3 g, and 18.9 g, and their respective coordinates after one particular throw are (0.479 m, -0.475 m), (-0.397 m, 0.297 m), and (-0.121 m, -0.433 m). What are the resulting coordinates of the center of mass of the dice, xcm and ycm?

xcm= ?

ycm=?

Explanation / Answer

let m1 = 11.9 g

m2 = 14.3 g

and m3 = 18.9 g

and (x1,y1) = (0.479m,-0.475m)

(x2,y2) = (-0.397m,0.297m)

and (x3,y3) = (-0.121m,-0.433m)

Xcm = [(m1*x1)+(m2*x2)+(m3*x3)]/(m1+m2+m3)

Xcm = [(11.9*0.479)-(14.3*0.397)-(18.9*0.121)]/(11.9+14.3+18.9)

Xcm = -0.05019 m

Ycm = [(m1*y1)+(m2*y2)+(m3*y3)]/(m1+m2+m3)

Ycm = [(-11.9*0.475)+(14.3*0.297)-(18.9*0.433)]/(11.9+14.3+18.9)

Ycm = -0.2126 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.