A 90.0 g ball of clay is thrown horizontally with a speed of 9.00 m/s toward a 8

Question

A 90.0 g ball of clay is thrown horizontally with a speed of 9.00 m/s toward a 850 g block resting on a frictionless surface. It hits the block and sticks. The clay exerts a constant force on the block during the 10.0 ms it takes the clay to come to rest relative to the block. After 10.0 ms, the block and the clay are sliding along the surface as a single system. What is their seed after the collision? Express your answers with appropriate units What is the force of the clay on the block during the collision? Express your answers with appropriate units What is the force of the block on the clay? Express your answers with appropriate units

Explanation / Answer

apply the law of conservation of momentu, we get

m * v = (m + M) * V  

V = m * v / (m + M) = 0.09 *9 / (0.09 + 0.85) = 0.86 m / s

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From impulse-momentum theorem, we get

F * t = p = m * v / t = m * (v - V) /t = 0.09 * 8.14 / 0.01

= 73.26 N

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the force of the block on the clay is equal to the for the force of the clay on block.

Then the force of the clay on the block is also 73.26 N

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