A 9.3 pound bucket about 3/4 full of water sits on a scale that reads 95.0 pound
ID: 3278991 • Letter: A
Question
A 9.3 pound bucket about 3/4 full of water sits on a scale that reads 95.0 pounds. A standard concrete block has two cores (as shown) and measures 7-5/8 x 7-5/8 x 15-5/8 inch on the outside. The block weighs 36.4 pounds and is lowered into the bucket and suspended by a rope that is attached to a spring scale. The block is completely in the water and no water spills out of the bucket. The spring scale reads 16.6 pounds after the concrete block is suspended in the water. Determine the following:
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4.44 pts.98%
Format Check
4.44 pts.98%
4.44 pts.98%
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4.44 pts.98%
(include units with answer)
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4.44 pts.98%
2% try penalty
Hints: 0,0 # tries: 0 B. The weight density of the block.
(include units with answer)
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4.44 pts.98%
2% try penalty
Hints: 2,0 # tries: 0 C. The material for the concrete block costs $3.50 per cubic foot. Determine the cost of a single block. ($)
4.44 pts.98%
2% try penalty
Hints: 0,0 # tries: 0 D. The reading of the scale the bucket rests on after the block is suspended.
(include units with answer)
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4.44 pts.98%
2% try penalty
Hints: 2,0 # tries: 0 E. The concrete block is now suspended in a new liquid. The spring scale reading is 19.3 pounds. Determine the weight density of the new liquid.
(include units with answer)
Explanation / Answer
weight of bucket = 9.3 pounds
Scale reading W = 95 pounds
mass of water, m = 95 - 9.3 = 85.7 pounds
density of water, rho = 0.0361273 pounds per cubic inch
a. so volume of water, V = m/rho = 2372.167 cu in^3
b. volume of block = V'
weight density of block = rho'
buoyant force on the block = rho*V' = 36.4 - 16.6 = 19.8 pounds
19.8 = 0.0361273*V'
V' = 548.0619 in ^3
so, weight density of block, rho' = 36.4/548.0619 = 0.06641 pounds per in^3
c. Volume of block = 548.0619 in ^3 = 548.0619/12*12*12 = 0.31716 ft^3
Cost of 1 ft^3 material = $3.5
cost of 0.31716 ft^3 material ( one blockl) = $1.11
d. After block is suspended
Reading of bucket scale = 95 + Buoyant force = 95 + 19.8 = 114.8 pounds
e. weight density of new liquid = rho"
then 36.4 - 19.3 = rho*548.0619
rho = 0.0312 pounds per cubic inch
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