A cannon elevated at some angle ? (unknown) fires a shell with some initial spee

Question

A cannon elevated at some angle ? (unknown) fires a shell with some initial speed v0 (unknown) that has a range R when fired over level ground (see Figure (a)). During a test fire, a shell explodes at the top of the trajectory into two unequal mass fragments. The shell explodes in such a manner that neither fragment experiences a change in momentum in the y direction. However, 38% of the shell (m2) continues onward and the other fragment (m1) falls straight down. Determine the distance D (in terms of R) that the forward moving fragment lands from the cannon (see Figure (b)). D =

Explanation / Answer

m2 = 0.38*M

m1 = 0.62 *M

t = V*sin(theta)/g

R = V^2*2*sin(theta)*cos(theta) / g

along x axis

m1*V1+m2*V2 = M*V*cos(theta)

0.38M*V1 + 0.62M *0 = M*V*cos(theta)

V1 = V*cos(theta) /0.38= 2.63V*cos(theta)

D = R/2+ V1*t

    = R/2 + 2.63(V*cos(theta) * V*sin(theta)/g)

    =R/2+1.315R

=1.815 R

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.