(a) Find the speed of the entangled vehicles after the collision answer 4.24 (b)

Question

(a) Find the speed of the entangled vehicles after the collision answer 4.24

(b) Find the change in the velocity of each vehicle

v truck -9.76

vcar 18.24

(c) Find the change in the kinetic energy of the system consisting of both vehicles

Pleas help me with the problems below!!!

Use the values from PRACTICE IT to help you work this exercise. Suppose the same two vehicles are both traveling eastward, the compact car leading the pickup truck. The driver of the compact car slams on the brakes suddenly, slowing the vehicle to 5.96 m/s. If the pickup truck traveling at 18.8 m/s crashes into the compact car, find the following.

(a) the speed of the system right after the collision, assuming the two vehicles become entangled?

(b) the change in velocity for both vehicles?

(c) the change in kinetic energy of the system, from the instant before impact (when the compact car is traveling at 5.96 m/s) to the instant right after the collision?

Explanation / Answer

given,

mass of truck = 1.71 * 10^3

velocity of truck = 14 m/s

mass of car = 9.15 * 10^2 kg

velocity of car = -14 m/s

initial momentum = 1.71 * 10^3 * 14 + 9.15 * 10^2 * -14

final momentum = (1.71 * 10^3 + 9.15 * 10^2) * v

by conservation of momentum

initial momentum = final momentum

1.71 * 10^3 * 14 + 9.15 * 10^2 * -14 = (1.71 * 10^3 + 9.15 * 10^2) * v

v = 4.24 m/s

speed of the entangled vehicles after the collision = 4.24 m/s

change in velocity of truck = 4.24 - 14

change in velocity of truck = -9.76 m/s

change in velocity of car = 4.24 - (-14)

change in velocity of car = 18.24 m/s

change in kinetic energy = 0.5 * 1.71 * 10^3 * 14^2 + 0.5 * 9.15 * 10^2 * 14^2 - 0.5 * (1.71 * 10^3 + 9.15 * 10^2) * 4.24^2

change in kinetic energy = 233654.4 J

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