A 1260 -kg car pushes a 2200 -kg truck that has a dead battery. When the driver

Question

A 1260 -kg car pushes a 2200 -kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the car push against the ground with a force of 4600 N . Take the friction between the truck's tires and the ground to be 470 N . What is the magnitude of the force the car applies to the truck?

A-) What is the magnitude FConT of the force that the car exerts on the truck? Use the coordinate system shown in Part B, where upward is the positive y direction and to the right, the direction FConT points, is the positive x direction.

B-) What is the acceleration aT of the truck?

Explanation / Answer

mass of the car m1=1260 kg

mass of the truck m2=2200 kg

force due to car on the ground is,F1=4600 N

frictional force between truck's tires and ground F2=470 N

here,

net force on the truck is,Fnet=(4600-470)=4130

A)

acceleration a=Fnet/(m1+m2)

a=4130/(1260+2200)

a=1.2 m/sec^2

force of car on the truck is,=m2*a

=2200*1.2

=2640 N

B)

acceleration a=1.2 m/sec^2

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