A spaceship is at a Lagrange point(where the gravity of earth and the sun balanc

Question

A spaceship is at a Lagrange point(where the gravity of earth and the sun balance out) and is about to head back to earth. if it has a mass of 175,000kg and can expel propellant from its engine at 12km/s, at what rate must it consume its propellant to achieve an acceleration of 0.1g? A spaceship is at a Lagrange point(where the gravity of earth and the sun balance out) and is about to head back to earth. if it has a mass of 175,000kg and can expel propellant from its engine at 12km/s, at what rate must it consume its propellant to achieve an acceleration of 0.1g? A spaceship is at a Lagrange point(where the gravity of earth and the sun balance out) and is about to head back to earth. if it has a mass of 175,000kg and can expel propellant from its engine at 12km/s, at what rate must it consume its propellant to achieve an acceleration of 0.1g?

Explanation / Answer

m =175000kg, a =0.1g , g =9.8 m/s^2, v =12 km/s

According to Newtos second law F =ma = dp/dt = v (dm/dt)

dm/dt = ma/v = (175000*0.1*9.8)/12000

dm/dt =14.3 kg/s

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