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Interactive LearningWare 7.1 reviews the approach that is necessary for solving

ID: 1346606 • Letter: I

Question

Interactive LearningWare 7.1 reviews the approach that is necessary for solving problems such as this one. A baseball (m = 153 g) approaches a bat horizontally at a speed of 36.5 m/s (81.7 mi/h) and is hit straight back at a speed of 50.0 m/s (112 mi/h). If the ball is in contact with the bat for a time of 1.16 ms, what is the average force exerted on the ball by the bat? Neglect the weight of the bat, since it is so much less than the force of the bat. Choose the direction of the incoming ball as the positive direction.

Explanation / Answer

Apply, Impuse-mometum theorem

Impulse = chnge in momentum

Favg*t = m*(vf - vi)

Favg = m*(vf - vi)/t

= 0.153*(-50 - 36.5)/(1.16*10^-3)

= -11409 N

here negative sign indicates the direction of force is opposite ti initial motion.

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