The figure below shows a zero-resistance rod sliding to the right on two zero-re

Question

The figure below shows a zero-resistance rod sliding to the right on two zero-resistance rails separated by the distance L = 1.75 m. The rails are connected by a 12 Ohm resistor, and the entire system is in a uniform magnetic field with a magnitude of 0.75 T. If the bar is moving to the left at 8 m/s at the moment shown, this means at this moment: The magnetic flux through the circuit will be: and causing an emf of V in the circuit. This emf creates an induced current in the circuit of: This will mean the power dissipated in the resistor at this moment will be: At this moment, the external B field is exerting a force on the bar of: This force acts like a form of magnetic

Explanation / Answer

L = 1.75 m

magnetic flux through the circuit is OUT OF THE PAGE

emf = B*v*L

emf = 0.75 * 1.75 * 8

emf = 10.5 V

the emf is 10.5 V

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induced current = emf/R

induced current = 10.5/12

induced current = 0.875 A

the direction of current is CLOCKWISE

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Power = 0.875^2 * 12 = 9.19 W

the power is 9.19 W

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Force = B*I*L

Force = 0.75 * 0.875 * 1.75

Force = 1.15 V

the force is 1.15 N

the direction of force is to the left which is oposite

bar tends to slow down

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