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http:// pling IN Summer Undergraduate Resea Muscular System Neuromuscular functi

ID: 1351426 • Letter: H

Question

http:// pling IN Summer Undergraduate Resea Muscular System Neuromuscular function after Human muscles-Google slide... Nebraska Wesley Universi... x C Chegg Shop Home & Garden P... a Amazon.com Online Sh... e eBay e Play Free Games e Suggested S e Web S Gallery Apple e Disney e ESPN e Yahoo! 11/3/2015 11:55 PM 0/10 Assignment Information Gradebook pts Print Period T Available From: 0/28/2 09:00 AM 015 Question 3 of 3 11/3/2015 11:55 PM Due Date: Map UNIVERSITY PHYSICS Points Possible: 10 has been Grade Category: Exit HW A bullet of s 13.5 g is fired toward a block of od at 253 m/s. The block is attached to a by spring that has a spring constant of 205 N As the bullet buries itself in the block, the block and bullet pti continue to move, compressing the spring by 35.0 cm before the whole system momentarily comes to a stop. Friction between block and surface is negligible. What is the mass of the wooden block? Homework (soln after due Policies: deduct MC) kg You can check your answers 205 N m. he d date. 253 m/s You can keep trying to answer each question until you get it right or give up 3.5 g You lose 5% of the points available to each For multiple-choice questions, the penalty depends on the number of choices available. eTextbook O Help With This Topic O Web Help & Videos E O Next Previous Check Answer Hint Copyright 20 2015 Sapling 52 privacy policy tact 2:27 PM /2/2015

Explanation / Answer

Given that,

mass = m = 13.6 g = 0.0136 kg; K = 205 N/m ; v = 253 m/s ; x = 35 cm = 0.35 m

Let the mass of the block be M.

From conservation of momentum:

P(i) = P(f)

m v = ( M + m) V

0.0136 x 253 = ( M + m) V

V = 3.441 / (M + m) (1)

Now, the potential energy of the spring after compression hould be equal to the intial kinetic energy of the bullet block system.

1/2 k x2 = 1/2 x (M + m) V2

205 x (0.35)2 = (M + m) V2 = 25.113

putting the value of V from (1) we get

(M + m) x [3.441 / (M + m) ]2 = 25.113

11.84 / (M + m) = 25.113

M + m = 0.47

M = 0.47 - m = 0.47 - 0.0136 = 0.46 kg = 45.64 g

Hence, mass of the wooden block = 0.46 kg.