12. The figure below is a cross - sectional view of a coaxial cable. The center

Question

12. The figure below is a cross - sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is I1 = 1.20 A out of the page and the current in the outer conductor is I2 = 2.98 A into the page. Assuming the distance d = 1.00 mm, answer the following. (a) Determine the magnitude and direction of the magnetic field at point a. (b) Determine the magnitude and direction of the magnetic field at point b.

Explanation / Answer

here,

I1 = 1.2 A

I2 = 2.98 A

d = 1 mm

d = 0.001 m

(a)

the magnitude of magnetic feild , B = u0*I1 /( 2 * pi * d) + u0 * I2 / ( 2 * pi * d)

B = 1.26 * 10^-6 * ( 1.2 + 2.98) / ( 2 * pi * 0.001)

B = 836 uT

the magnetic feild is 836 uT and the direction is upwards

(b)

the magnitude of magnetic feild , B = |u0*I1 /( 2 * pi * 3 * d) - u0 * I2 / ( 2 * pi * d)|

B = |1.26 * 10^-6 * 1.2 /( 2 * pi * 3 * 0.001) - 1.26 * 10^-6 * 2.98 / ( 2 * pi * 0.001) |

B = 5.17 * 10^-4 T

B = 517 uT

the magnetic feild is 517 uT and the direction is downwards

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