2:00:00 PM (27%) Problem 8: Ir, the coordinate system shown at right, particle 1

Question

2:00:00 PM (27%) Problem 8: Ir, the coordinate system shown at right, particle 1 with charge 9,-9, where q = 1.8 pC, is located at coordinates (-a, Ob m, where = 6A particle 2 with charge 92-2q is located at coordinates (a·Ok particle 3 with charge 93- is located at cooedinates (0, a) 1 (-a, 0) 2 (a,0) theexpertta.com #14% Part (a) Find the electric potential at the origin symbols given. express it using the detailed vie hore an charges 14% Part (b) Solve for the numerical value of Vo in J/C 14% Part (c) Using to denote the direction of the electric field at the origin EO measured counterclockwise from the positive x-axis, find tan(). 14% Part (d) Now find sin() 14% Part (e) Solve for the numerical value of . (Suppose a is between 0 and 360°.) in the origin given 14% Part (g) Solve for the numerical value for the magnitude of E0 in N/C

Explanation / Answer

V0 = V1+V2+V2

V1 = k*q/a= (9*10^9*4.8*10^-6)/6.8 = 6353 V

V2 = k*2*q/a = 2*6353 = 12706 V

V3 = k*q/a = 6353 V

A) Vo = 4*k*q/a

B) then Vo = 6353+12706+6353 = 25412 V

C) along x-axis Ex = k*(q-2q)/a^2 = (9*10^9*4.8*10^-6)/(6.8*6.8) = 934.25 V/m

along Y-axis Ey = 934.25 V/m

tan (alpha) = (-934.25/934.25) =-1

D) sin(alpha) = 0.707

e) alpha = atan(-1) = 135 degrees

f) Eo = 1.414*k*q/a^2

g)Eo = 1.414*934.25 = 1321.02 N/C

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