Two mirrors are placed perpendicular to each other. A beam of light reflects off

Question

Two mirrors are placed perpendicular to each other. A beam of light reflects off mirror 1 with incident angle theta = 74 degrees, then reflects off mirror 2 with angle theta_f. If the angle the light reflected from mirror 1 is theta, express theta, in terms of theta. If the incident angle of the light on mirror 2 is theta_2, express theta_2: in terms of theta_i. Express theta_f in terms of theta_i Solve for the numerical value of theta_f in degrees. What is the relation between the direction of the incident light and the direction of the emitted light?

Explanation / Answer

here,

(a)

as the angle of reflection is equal to the angle of incidence ,

theta1 = thetai

(b)

for the triangle formed at the joint of the mirror

90 + (90 - theta2) + (90 - theta1) = 180

theta1 + theta2 = 90 degree

and from part (1) , theta1 = theta i

theta 2 = 90 - theta i

(c)

as the angle of reflection is equal to the angle of incidence ,

theta f = theta 2

theta f = 90 - theta i

(d)

theta i = 74 degree

therefore ,

theta f = 90 - 74

theta f = 16 degree

the angle theta f is 16 degree

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