Three blocks are stacked on top of each other inside an elevator as shown in (Fi

ID: 1358046 • Letter: T

Question

Three blocks are stacked on top of each other inside an elevator as shown in (Figure 1) .

Answer the following questions with reference to the eight forces defined as follows.

the force of the 3 kg block on the 2 kgblock, F3on2,

the force of the 2 kg block on the 3 kgblock, F2on3,

the force of the 3 kg block on the 1 kgblock, F3on1,

the force of the 1 kg block on the 3 kgblock, F1on3,

the force of the 2 kg block on the 1 kgblock, F2on1,

the force of the 1 kg block on the 2 kgblock, F1on2,

the force of the 1 kg block on the floor, F1onfloor, and

the force of the floor on the 1 kg block, Fflooron1.

Assume the elevator is at rest. Rank the magnitude of the forces.

Rank from largest to smallest. To rank items as equivalent, overlap them.

here the forces from largest to smallest is

1. F(1 on the floor) & F(floor on 1)

2. F(1 on 2) & F(2 on 1)

3. F(2 on 3) & F(3 on 2 )

4. F(3 on 1) & F(1 on 3)

Force,F1,of 3kg block on the 2kg block,F of 3 on 2=3*9.81= 29.43N

Force, F2, of 2kg block on the 3kg block, F of 2 on 3=3*9.81= 29.43N

Force,F3 of 3kg block on the 1kg block, F of 3 on 1=0N(not in contact)

Force,F4 of the 1kg block on the 3kg block, F of 1 on 3, = 0 N

Force,F5 of 2kg block on 1kg block,F of 2 on 1=29.43+2*9.81=49.05 N

Force,F6 of the 1kg block on the 2kg block, F of 1 on 2, = 49.05N

Force,F7 of the 1kg block on the floor, F of 1 on floor, and =58.86 N

Force,F8 of the floor on the 1kg block, F of floor on 1= 58.86N

Gravitational forces between blocks are neglected.

Magnitudes of all forces are ordered as F7 >F5>F1>F3

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