on a rainy On a rainy evening, a 10,000 N truck is driving along a straight, lev
ID: 1358523 • Letter: O
Question
on a rainy On a rainy evening, a 10,000 N truck is driving along a straight, level road at 25 m/s. The driver panics when a deer runs onto the road and locks the wheels while braking. The coefficient of kinetic friction for the wheel/road interface is 0.68. The frictional force between the wheel/road interface causes the truck to slow down and stop. What is the frictional force acting on the truck? Determine the deceleration of the truck as it stops. How far does the truck travel before stopping?Explanation / Answer
given,
weight of truck = 10000 N
speed of truck = 25 m/s
coefficient of kinetic friction = 0.68
frictional force = k * mg
frictional force = 0.68 * 10000 * 9.8
frictional force = 66640 N
deceleration = friction force / mass
deceleration = 66640 / 10000
deceleration = 6.664 m/s^2
v^2 = u^2 + 2as
0 = 25^2 - 2 * 6.664 * s
s = 46.89 m
truck will travel 46.89 m before stopping
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