A 9 kg crate is moved from the ground up a loading platform 6.1 m long and 2.5 m
ID: 1359561 • Letter: A
Question
A 9 kg crate is moved from the ground up a loading platform 6.1 m long and 2.5 m high. Assume the coefficient of kinetic friction is 0.23. What is the actual mechanical advantage and incline plane efficiency?
Actual MA = [Num]
Incline Efficiency = [Num]%
A 9 kg crate is moved from the ground up a loading platform 6.1 m long and 2.5 m high. Assume the coefficient of kinetic friction is 0.23. What is the actual mechanical advantage and incline plane efficiency?
Actual MA = [Num]
Incline Efficiency = [Num]%
Explanation / Answer
here,
b = 6.1 m
p = 2.5 m
uk = 0.23
mass = 9 kg
h = sqrt(6.1^2 + 2.5^2)
h = 6.59
cosA = b/h = 6.1 / 6.59
CosA = 0.92
A = 23.07 degrees
Mechanical advantage for Inclined plane, is given as
MA = X / Y
Where,
X = Ratio of the force you have to apply for meeting the objective without using the tool.
Y = Force you have to apply for meeting your objective using the tool.
Hence
MA = 1 / sinA + ff
MA = 1 / (sin23.07 + uk*cos23.07 )
MA = 1 /(0.39+0.23*0.92)
MA = 1.662
actual mechanical advantage 1.662
Efficiency = Ideal mechanical advantage / actual mechanical advantgae
% = sinA/(1.662)
% = 0.39/1.662
% = 0.235 *100
% =23.5 percent
Incline Efficiency is 23.5 %
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