This question requires a numeric or algebraic? Answer. In order to receive full

Question

This question requires a numeric or algebraic? Answer. In order to receive full credit for this problem, you must show all your work. To show your work for this problem, you may scan neatly handwritten work or type up your work in MS Word using the equation editor and submit it using the Final Exam Dropbox. You should make your submissions after you complete the exam. A 1. 0-cm diameter pipe widens to 2. 0 cm and then narrows to 5. 0 mm. Liquid flows through the first segment at a speed of 4. 0 m/s. What is the speed of the liquid in the second and third segments of pipe? What is the volume flow rate through the pipe?

Explanation / Answer

here,

initial speed , u1 = 4 m/s

initial diameter , d1 = 1 cm

radius ,r1 = 0.005 m

seccond diameter , d2 = 2 cm

seccond radius , r2 = 0.01 m

third diameter , d3 = 5 mm

third radius , r3 = 0.0025 m

let the speed at seccond and third segment of pipe be v2 and v3

using equation of continuity

Area1 * velocity 1 = aArea 2 * volume 2

pi * r1^2 * u1 = pi * r2^2 *v2

0.005^2 * 4 = 0.01^2 * v2

v2 = 1 m/s

using equation of continuity

Area1 * velocity 1 = Area 3 * volume 3

pi * r1^2 * u1 = pi * r3^2 *v3

0.005^2 * 4 = 0.0025^2 * v3

v3 = 16 m/s

the speed in third segment is 16 m/s and seccond segment is 1 m/s

the volume flow rate of the pipe , V = area1 * velocity1

V = 1 * 10^-4 m^3/s

the volume flow rate is 1 * 10^-4 m^3/s

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