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A 35-kg child is holding on for dear life on a playground merry goround that has

ID: 1364168 • Letter: A

Question

A 35-kg child is holding on for dear life on a playground merry goround that has a radius of 2. 5 m and is turning at a rate of one turn every 5. 0 s. What is the child's acceleration relative to the ground? What is the magnitude of the force acting on the child through the child's arms? What is the child's acceleration relative to the place on the merrygoround where the child is standing? If you were to naively apply Newton's second law to this situation, what is the magnitude of the apparent centrifugal force acting on the child?

Explanation / Answer

a) a = V^2/R

V = 2piR/T

=> a = 4*pi^2*R/T^2 = 4*3.14*3.14*2.5/(5^2) = 3.94 m/s^2

b) F = mV^2/R = 35*3.94 = 137.9 N

c) 0

d)

F = mV^2/R = 35*3.94 = 137.9 N

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