A 2. 0-kg mass is pushed against a spring until it is compressed by x= 0. lm and

Question

A 2. 0-kg mass is pushed against a spring until it is compressed by x= 0. lm and is then released. The block leaves the spring and slides up a frictionless ramp onto a frictionless surface a vertical distance, h. above the lower frictionless plane as shown. h=0. 20m k=1960 N/m What is the initial potential energy of the spring-mass system? Ans 9. 80 J What is the speed. Vf, of the block when it is on the upper surface? Ans 2. 42 m/s Block A in the figure weighs 100N. The coefficient of static friction between block B and the horizontal surface is 0. 25. What is the tension in the string attached to the wall? Ans 200 N Find the minimum weight of block B for which the system will be in equilibrium. Ans 693 N

Explanation / Answer

here,

mass of block = 2 kg
h = 0.20 m
x = 0.1 m
k = 1960 N/m

A)

Potential Energy in spring :

U = 0. 5 * K * X^2
U = 0.5 * 1960 * 0.1^2
U = 9.8 J

B)

From Conservation of Energy we have

Kinetic Energy = Potential energy at top

0.5 * M * V^2 = M * g * H

V = Sqrt(2 * g * h)

V = sqrt( 2 * 9.8 * 0.20)

V = 1.97 m/s

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