A capacitor is made from two hollow, coaxial, iron cylinders, one inside the oth

Question

A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is 12.0 pC . The inner cylinder has a radius of 0.450 mm , the outer one has a radius of 4.20 mm , and the length of each cylinder is 15.0 cm .

Part A

What is the capacitance?

Use 8.854×1012 F/m for the permittivity of free space.

4.90

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Part B

What applied potential difference is necessary to produce these charges on the cylinders?

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A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is 12.0 pC . The inner cylinder has a radius of 0.450 mm , the outer one has a radius of 4.20 mm , and the length of each cylinder is 15.0 cm .

Part A

What is the capacitance?

Use 8.854×1012 F/m for the permittivity of free space.

C =

4.90

F

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Incorrect; Try Again; 5 attempts remaining

Part B

What applied potential difference is necessary to produce these charges on the cylinders?

V = V

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Explanation / Answer

charge on capacitor q=12*10^-12 C

inner radius r1=0.45 mm =0.45*10^-3 m

outer radius r2=4.2 mm = 4.2*10^-3 m

length of cylinder l=15cm=0.15m

A)

capacitance of cylindrical capacitor is,

C=(2pi*eo*l)/(ln(r2/r1)

C=(2pi*8.854*10^-12*0.15)/(ln(0.45*10^-3/(4.2*10^-3)

C=3.74*10^-12 F

B)

potential v=q/c

v=(12*10^-12)/(3.74*10^-12)

v=3.21 v

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