A square loop of wire, of side length 5 cm, is placed on the edge of a magnetic

Question

A square loop of wire, of side length 5 cm, is placed on the edge of a magnetic field of strength 4.2 T into the page. This field can be described as a section of the xy plane with and equation x<0 and the loop is oriented so that it is in the xy plane with each side pointing purely along the x or y direction. The loop also starts entirely inside the magnetic field The wire loop is then pulled in the +x direction. The position of the edge of the loop can be described by the equation x = 5*t^2+5*t, which is measured in seconds and cm. Determine the force, in N, caused by the induced current at time t=1s.

Explanation / Answer

e = Bvl

v= dx/dt = 10t + 5

at t = 1s

v = 15

F =BIL

B = uo*I/2pi*L

I = B*L/2*10^-7

F = 2.21 x 10^5 N

or

F= qVB

F = 1.6 x 10^-19 x 15 * 4.2 = 1.008 x 10^-17

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