Any object with electric charge, stationary or moving, other than the charged ob
ID: 1364991 • Letter: A
Question
Any object with electric charge, stationary or moving, other than the charged object that created the field experiences a force in an electric field. Also, any object with electric charge, stationary or moving, can create an electric field. Similarly, an electric current or a moving electric charge, other than the current or charge that created the field, experiences a force in a magnetic field, and an electric current creates a magnetic field.
Any object with electric charge, stationary or moving, other than the charged object that created the field experiences a force in an electric field. Also, any object with electric charge, stationary or moving, can create an electric field Similarly, an electric current or a moving electric charge, other than the current or charge that created the field, experiences a force in a magnetic field, and an electric current creates a magnetic field. (a) To understand how a moving charge can also create a magnetic field, consider a particle with charge q moving with velocity V. Define the position vector r f leading from the particle to some location. Show that moving with velocity v . Define the position vector r = rr leading from the particle to some location. Show that the magnetic field at that location is r2 n the wok.) 4 (b) Find the magnitude of the magnetic field 1.24 mm to the side of a proton moving at 2.10 x 107 m/s 2.185e-13 T (c) Find the magnetic force on a second proton at this point, moving with the same speed in the opposite direction magnitude 7.34e-25 direction away from the first proton (d) Find the electric force on the second proton. 1.49e-18 magnitude Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. N direction away from the first protonExplanation / Answer
According to Coulomb's l law,
F(electrc) = q1 x E
=k q1 q2/ r^2;
K=9 x 10^9, q1 = q2 = 1.6 x 10^-19, r =1.24 x 10^-3.
F(electric) = (9 x 10^9)(1.6 x 10^-19)(1.6 x 10^-19)/ (1.24 x 10^-3)^2
= 14.98 x 10^(9-19-19+6)
= 1.498 x 10-22 (repulsive)
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