1-Monochromatic light from a distant source is incident on a slit 0.720 mm wide.

Question

1-Monochromatic light from a distant source is incident on a slit 0.720 mm wide. On a screen 2.14 m away, the distance from the central maximum of the diffraction pattern to the first minimum is measured to be 1.33 mm .

Calculate the wavelength of the light in meter.

2-An astronaut in orbit can just resolve two point sources on the earth that are 82.0 m apart. Assume that the resolution is diffraction-limited and use Rayleigh's criterion. What is the astronaut's altitude above the earth? Treat her eye as a circular aperture with a diameter of 4.00 mm (the diameter of her pupil), and take the wavelength of the light to be 600 nm .

find h . in km

Explanation / Answer

d = 0.72 mm = 0.72 * 10^-3 m
L = 2.14 m
y = 1.33 * 10^-3

y = m**L/d
For 1st Minima, m =1
1.33 * 10^-3 = 1** 2.14 /(0.72 * 10^-3)
Solving for
= 4.4747 * 10^-7 m

Wavelength of light in m, = 4.475 * 10^-7 m

Please post seperate question in seperate post.

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