Using the values given in the previous problem, the ratio of the energy immediat

Question

Using the values given in the previous problem, the ratio of the energy immediately after and before the collision of the system consisting of the ball and the catcher, KE_after/KE_before is Question 4 options: 0.06 0.26 0.37 1.00 None of the above

Suppose you conduct the ballistic pendulum experiment and find that the max angle of the ballistic pendulum was 10 degrees. In the experiment the length of the pendulum was 25cm, the mass of the metal ball was 70g, the mass of the catcher was 200g, and the height of the gun relative to the ground was 1m. What would be the range of the metal ball, the horizontal distance the metal ball travels before hitting the ground when the gun is fired without the catcher?

48cm

85cm

95cm

100cm

Explanation / Answer

48cm is the correct answer.

height raised above its initial position, h = L*(1 - cos(10))

= 0.25*(1 - cos(10))

= 0.003798 m

speed of the catcher and metaal ball after the collsion,

v = sqrt(2*g*h)

= sqrt(2*9.8*0.003798)

= 0.2728 m/s

let u is speed of metal ball before the collson.

now Apply conservation of momentum

m1*u1 = (m1+m2)*v

u1 = (m1+m2)*v/m1

= (70 + 200)*0.2728/70

= 1.05 m/s

let t is the time taken to his the ground if catcher is not present.

Apply, H = 0.5*g*t^2

t = sqrt(2*H/g)

= sqrt(2*1/9.8)

= 0.4517 s

so, distance travelled before striking the ground,

x = u*t

= 1.05*0.4517

= 0.474 m

= 47.4 cm (approximately 48 cm)

Related Questions

Navigate

• Browse (All)
• Browse U
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.