A certain type of perpendicular blade can be modeled as a thin uniform at 2.5 lo

Question

A certain type of perpendicular blade can be modeled as a thin uniform at 2.5 long and of mass 22.0kg that is free to rotate about a frictionless axis perpendicular to the bar at its mid point.If a technician strikes this blade with a mallet 1.15m from the center with 35.0N force perpendicular to the blade.find the maximum angular acceleration the blade could achieve? A certain type of perpendicular blade can be modeled as a thin uniform at 2.5 long and of mass 22.0kg that is free to rotate about a frictionless axis perpendicular to the bar at its mid point.If a technician strikes this blade with a mallet 1.15m from the center with 35.0N force perpendicular to the blade.find the maximum angular acceleration the blade could achieve?

Explanation / Answer

The angular acceleration is

= T/I, where T = torque applied and I = moment of inertia.
T = f*d
T = 35*1.15 = 40.25 N-m
I = M*L²/12 = 22.0*2.5²/12 = 11.45 kg*m²

= 3.51 rad/s²

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