Q#1 :An AM radio transmitter broadcasts 50.0 kW of power uniformly in all direct

Question

Q#1:An AM radio transmitter broadcasts 50.0 kW of power uniformly in all directions. Assuming all of the radio waves that strike the ground are completely absorbed, and that there is no absorption by the atmosphere or other objects, what is the intensity 29.0 km away? (Hint: Half the power will be spread over the area of a hemisphere.)
A#1: 4.73

Q#1:An AM radio transmitter broadcasts 50.0 kW of power uniformly in all directions. Assuming all of the radio waves that strike the ground are completely absorbed, and that there is no absorption by the atmosphere or other objects, what is the intensity 29.0 km away? (Hint: Half the power will be spread over the area of a hemisphere.) A#1: 4.7310-6 W/m^2 Q#2:What is the maximum electric field strength at this distance? A#2: Please provide answer #2 and show all work.

Explanation / Answer

here by using

electric field = (sqrt30*P) / d

E = (sqrt30 * 25000) / 29000

E = 866.02 / 29000

E = 0.0298 V / m

the electric field strength at the distance of 29000 m is 0.0298 V/m

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