Exercise 26.42 A 12.4? ? F capacitor is connected through a 0.885?M? resistor to
ID: 1374480 • Letter: E
Question
Exercise 26.42
A 12.4??F capacitor is connected through a 0.885?M? resistor to a constant potential difference of 60.0 V.
Part A
Compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 s.
Express your answers using two significant figures. Enter your answers numerically separated by commas.
Part B
Compute the charging currents at the same instants.
Express your answers using two significant figures. Enter your answers numerically separated by commas.
Explanation / Answer
V(t) = V0 [ 1 - e^(-t /RC) ]
V(t) = 60 [ 1 - e(-t / 10.97)]
Part (A)
V(0) = 0
V(5) = 60 [ 1 - e(-5 / 10.97)] = 21.96 V
V(10) = 60 [ 1 - e(-10 / 10.97)] = 35.88 V
V(20) = 60 [ 1 - e(-20 / 10.97)] = 50.310 V
V(100) = 60 [ 1 - e(-100 / 10.97)] = 59.99 V
Part (B)
I(t)*R = IR [ 1 - e(-t / 10.97)]
I(t) = (6.78 x 10^-5) [ 1 - e(-t / 10.97)]
I(0) = 0
I(5) = (6.78 x 10^-5) [ 1 - e(-5 / 10.97)] = 2.48 x 10^-5 A
I(10) = (6.78 x 10^-5)[ 1 - e(-10 / 10.97)] = 4.05 x 10^-5 A
I(20) =(6.78 x 10^-5)[ 1 - e(-20 / 10.97)] = 5.68 x 10^-5 A
I(100)= (6.78 x 10^-5)[ 1 - e(-100 / 10.97)] = 6.78 x 10^-5 A
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.