Exercise 26.42 Part A You connect a battery, resistor, and capacitor as in (Figu

Question

Exercise 26.42 Part A You connect a battery, resistor, and capacitor as in (Figure 1), where R-15.0 and C = 8.00 × 10-6 F. The switch S is closed at t = 0 When the current in the circuit has magnitude 3.00 A, the charge on the capacitor is 40.0 x 10.6 C. What is the emf of the battery? Express you r answer with the appropriate units. EValue Units Submit My Answers Give Up Incorrect, Iry Again; 3 attempts remaining Part B At what time t after the switch is closed is the charge on the capacitor equal to 40.0 × 10-6 C? Express your answer with the appropriate units. Fi l of 1 Switch open t= Value Units Submit My Answers Give Up i=0 q=0 Part C When the current has magnitude 3.00 A, at what rate is energy being stored in the capacitor? Express your answer with the appropriate units.

Explanation / Answer

Given R = 15 ohm

C = 8 * 10^-6 F

I = 3 A

q = 40 * 10^-6 C

part A

emf e = (I * R) + (q/C)

e = (3 * 15) + (40 / 8)

e = 50 V

part B

q = Q * (1-e^(-t/RC))

Q = C * V

Q = 40 * 10^-6 * 50

Q = 2000 * 10^-6 C

RC = 15 * 40 * 10^-6 = 0.0006 s

40 * 10^-6 = 2000 * 10^-6 * (1 - e^(-t/0.0006))

t = 1.21 * 10^-5 s

part C

P = V * I

P = (q/C) * I

P = (40/8) * 3

P = 15 W---------------energy being stored in capacitor

part D

P = V * I

P = 50 * 3

P = 150 W----------------------------energy being supplied by the battery

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.