A uniform 8.00m , 1550kg beam is hinged to a wall and supported by a thin cable

Question

A uniform 8.00m , 1550kg beam is hinged to a wall and supported by a thin cable attached 2.00m from the free end of the beam, as shown in the figure below (Figure 1) . The beam is supported at an angle of 30.0? above the horizontal.

Part A

Find the tension in the cable.

1.37

T =

1.37

A uniform 8.00m , 1550kg beam is hinged to a wall and supported by a thin cable attached 2.00m from the free end of the beam, as shown in the figure below (Figure 1) . The beam is supported at an angle of 30.0? above the horizontal. Part A Find the tension in the cable. T = 1.37?104 N Part B How hard does the beam push inward on the wall? F = ??

Explanation / Answer

B)

Here , let the x-compoent of force on wall is Fx

y -component of force is Fy

Now,

Balacning forces on the rod in x-axis

T*cos(40) - Fx = 0

Fx = 1.37 * 10^4 * cos(40)

Fx = 10494.8 N

Now , balacing the y-forces

T*sin(40) - mg + Fy = 0

Fy = 1550 * 9.8 - 1.37*10^4 * sin(40)

Fy = 1490 N

Hence , the force of beam on wall = sqrt(Fx^2 + Fy^2)

the force of beam on wall = sqrt(10496.8^2 + 1490^2)

the force of beam on wall = 10600 N

the beam push the wall with a force of 10600 N

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