The circuit of (Figure 1) is a square 5.1cm on a side. The magnetic field increa

Question

The circuit of (Figure 1) is a square

5.1cm on a side. The magnetic field increases steadily from 0 T to 0.55T in 13ms .

Part A

What is the current in the resistor during this time?

Express your answer to two significant figures and include the appropriate units.

The circuit of (Figure 1) is a square 5.1cm on a side. The magnetic field increases steadily from 0 T to 0.55T in 13ms . Part A What is the current in the resistor during this time? Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

From Faraday's law,

V=A*B/t

But we can take ohm's law then

IR=A*B/t

rearrange the expression

I=A*B/R*t ......(1)

A is the area of square, A=a^2 ,B is the magnetic field , R is the resistance in the circuit, t is the time .

we can substitute values in equation (1)

I=(5.1*10^-2 m*5.1*10^-2 m*0.55 T)/(20 ohm *13*10^-3 s)

=0.0055 A

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