Thank you very much! Two parallel rails having negligible resistance are connect
ID: 1378685 • Letter: T
Question
Thank you very much!
Two parallel rails having negligible resistance are connected by a resistor. The circuit also contains two metals rods with resistance, one with moving to the left and the other moving to the right. At t = 0 seconds the rods are 5 cm from the 6 ohm resistor. The rods are sliding along the rails and moving away from the 6 ohm resistor ar constant velocities as shown in figure below. A uniform magnetic field is applied perpendicular to the plane of the rails. Note: Drawing not to scale. Determine the magnitude of the current in the 6 ohm resistor ar t = 5s. {Be careful - this is multiple-loop circuit.} Answer in units of mA.Explanation / Answer
induced emf in the moving rod = B*v*L
= 0.0118*2*0.1
= 2.36*10^-3 volts
net resistance of the ckt, Rnet = 13 + 6*17/(6+17)
= 17.43 ohms
current through 13 ohm resistor, I = induced emf/Rnet
= 2.36*10^-3/17.43
= 0.135 mA
current through 6 ohms = I*17/(6+17)
= 0.1 mA <<<<<<--------Answer
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.