A 49 % dextrous solution (49 mg per 100 mL of solution) is given intravenously.

Question

A 49 % dextrous solution (49 mg per 100 mL of solution) is given intravenously. Suppose a total of 1.782 L of the solution is given over a 11 -hour period. Complete parts (a) through (c) below.

a. What is the flow rate in units of mL/hr? nothing mL/hr (Type an integer or decimal rounded to the nearest thousandth as needed.) What is the flow rate in dextrous per hour? mg/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)

b. If each mL contains 15 drops (the drop factor is expressed as 15 ggt/mL), what is the flow rate in units of ggt/hr? nothing ggt/hr (Type an integer or decimal rounded to the nearest thousandth as needed.)

c. During the 11 -hour period, how much dextrous is delivered? nothing mg (Type an integer or decimal rounded to the nearest thousandth as needed.)

Explanation / Answer

1)a . Dextrose solution 49 %= 49 gm in 100ml

Total solution transfused =1.782liter

Total time =11hrs

Flow rate = total volume of solution/total time in hr

= First convert liter to ml

= 1.782 liter × 1000 is equal to 1782 ml

Flow rate = 1782 ml/ 11 hr = 162ml/hr

1)b Dextrose in 100 ml of solution = 49 mg

49 mg in 100ml ,then in 1782 ml how many mg :-

100ml has 49 mg dextrose

1 ml has 49/100mg

1782 ml has =49/100 ×1782 = 873.1 ~873 mg dextrose

Now, flow rate mg/hr = 873mg / 11hr

= 79.3 mg /hr ~79mg/ hr.

2. Now, drop factor is given 15 gtt/ min

Then flow rate = total volume in ml / total time in min × drop factor

= 1782ml/ 11×60 min ×15

= 2.7×15 = 40.5 ml/min ~40 ml/min

3. During the 11hr period Dextrose delivered in mg is

In each hour the mg of dextrose delivered = 79mg

So, in 11 th hour the mg will be =79 mg

Making a total of 873 mg in 11 hrs.

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