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A glass marble is dropped down an elevator shaft and hits a thick glass plate on

ID: 1380975 • Letter: A

Question

A glass marble is dropped down an elevator shaft and hits a thick glass plate on top of an elevator that is descending at a speed of 2.60 m/s. The marble hits the glass plate 6.0 m below the point from which it was dropped. If the collision is elastic, how high will the marble rise, relative to the point from which it was dropped? A glass marble is dropped down an elevator shaft and hits a thick glass plate on top of an elevator that is descending at a speed of 2.60 m/s. The marble hits the glass plate 6.0 m below the point from which it was dropped. If the collision is elastic, how high will the marble rise, relative to the point from which it was dropped?

Explanation / Answer

the point of impact have potential energy = 0,

which would make the top of the fall have a

PE =mgh=m*9.8*6=58.8m

58.8m = 0.5mv^2.

v=10.84m/s

relative velocity=10.84-2.6

=8.24m/s

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