Two strings are adjusted to vibrate at exactly 280Hz . Then the tension in one s

Question

Two strings are adjusted to vibrate at exactly 280Hz . Then the tension in one string is increased slightly. Afterward, three beats per second are heard when the strings vibrate at the same time.What is the new frequency of the string that was tightened? Two strings are adjusted to vibrate at exactly 280Hz . Then the tension in one string is increased slightly. Afterward, three beats per second are heard when the strings vibrate at the same time.What is the new frequency of the string that was tightened?

Explanation / Answer

frequency of vibration is given by :

f = sqrt(T/(m/L))/2L = 280

when the tension is changed to say , T',

f' = sqrt(T'/(m/L))/2L

Now, beat frequency, B = f' -f = 3

So, f' = f + 3 = 280 + 3 = 283 Hz <-------answer

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