pling A ring of charge is centered at the origin in the vertical direction. The

Question

pling A ring of charge is centered at the origin in the vertical direction. The ring has a charge density of A 5.46 x 105 C/m and aradius of R 3.27 cm. Find the total electric field, E, of the ring at the point P (1.10 m, 0.00 m). The Coulomb force constant is k 1/(4meo) 8.99 x 109 N m2/c2 Number E- 29993.78 da Find the expression for the electric field, EN, of the ring dE as the point P becomes very far from the ring (x R) in terms of the radius R, the distance x, the total charge on the ring q, and the constant k 1/ 4meo. There is a hint available! View the hint by clicking on the divider bar again to hide the hint. Close Map

Explanation / Answer

A)

here ,

electric field due to ring is given as

E = k*x*2*pi*R * charge density /(x^2 + R^2)^1.5

E = 9 * 10^9 * 2*pi*0.0327 * 1.1*5.46 *10^-6 /(1.1^2 + 0.0327^2)^1.5

E = 8331.4 N/C

the electric field is 8331.4 N/C

B)

E = k*x*2*pi*R * charge density /(x^2 + R^2)^1.5

for x >> R

E = k*x*Q /(x^2)^1.5

E = k*Q/x^2

the electric field at large distance is k*Q/x^2

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