Two passenger trains A and B, each 220 m long, pass a 50 m long railroad platfor

Question

Two passenger trains A and B, each 220 m long, pass a 50 m long railroad platform in Winnepeg. The trains are moving in opposite directions at equal speeds of 0.505c with respect to the ground. Train A is traveling west and all tracks are perfectly straight. The Winnepeg stationmaster, knowing the speed of train A, measures its length as it passes him by measuring the difference between the arrival times of the front of the train and the rear of the train.

According to clocks in the station and on both trains it is exactly 12:00 noon when both trains arrive in Winnepeg. How many seconds later should the stationmaster in Vancouver, 1900 km to the west, expect train A to arrive?

Explanation / Answer

T = d/v = 1900000 / 0.505c = 1900000/(0.505*3.00

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