The switch in the circuit has been open for a long time. Immediately after it is

Question

The switch in the circuit has been open for a long time. Immediately after it is closed, what is the CURRENT through THE INDUCTOR? E / R1 0 E / (R1 + R2) E / L E / R2 Tries 0 / 1 Immediately after the switch has been closed, what can you say about the current in R1 ? It is the same as the current in R2, and they are both equal to zero. It is zero, and not the same as the current through R2 It is greater than the current through R2 It is the same as the current in R2, but greater than zero. What is the correct loop rule for a loop that goes through the battery, the inductor, and Resistor 1? +E - Delta VL - I1 R1 = 0 +E - Delta VL - I1 R1 - I2 R2 = 0 +E - It R1 = 0 +E - Delta VL + I1 R1 = 0 +E - L - I1 R1 = 0 Tries 0 / 1 Immediately after the switch is closed, what is the VOLTAGE across the INDUCTOR? I L E - I1 R1 E-I2 R2 0 Tries 0 / 1

Explanation / Answer

Just after closing the circuit there is no current in the inductor. For this reason at the same time the current in the two resistors is the same (they are serially connected and its greater than 0).

The correct lopp equation for question3) is a). This is beacuse the generator tension and the voltage drops at the edges of the loppe lements must have opposite signs.

Inductor voltage is null, sinceit's the current time derivatime times the iductance value.

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