A certain man has a mass of 76 kg and a density of 992 kg/m 3 (excluding the air

Question

A certain man has a mass of 76 kg and a density of 992 kg/m3 (excluding the air in his lungs).

Randomized Variablesm = 76 kg
? = 992 kg/m3 Part (a) Calculate his volume in cubic meters.
Numeric   : A numeric value is expected and not an expression.
V = __________________________________________


Part (b) Find the buoyant force, in newtons, that air exerts on him. Use 1.29 kg/m3 for the density of air.
Numeric   : A numeric value is expected and not an expression.
FB = __________________________________________


Part (c) What is the ratio of the buoyant force to his weight?
Numeric   : A numeric value is expected and not an expression.
FB/w = __________________________________________ A certain man has a mass of 76 kg and a density of 992 kg/m3 (excluding the air in his lungs).

Randomized Variablesm = 76 kg
? = 992 kg/m3 Part (a) Calculate his volume in cubic meters.
Numeric   : A numeric value is expected and not an expression.
V = __________________________________________


Part (b) Find the buoyant force, in newtons, that air exerts on him. Use 1.29 kg/m3 for the density of air.
Numeric   : A numeric value is expected and not an expression.
FB = __________________________________________


Part (c) What is the ratio of the buoyant force to his weight?
Numeric   : A numeric value is expected and not an expression.
FB/w = __________________________________________

Explanation / Answer

Solution: Part a: the volume of the man V = M/D = 0.0766 m3.

Part b: The magnitude of buoyant force that air will exert on him is = 0.099 kg-wt.

Part c: The ratio of buoyant force to his weight is = 0.099 kg-wt / 76 kg-wt = 1.3x10-3.

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