As a woman walks, her entire weight is momentarily placed on one heel of her hig

Question

As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. This creates quite a large pressure on the ground - in fact, in the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were too thin to withstand such large pressures.

Randomized Variablesm = 51.5 kg
A = 1.25 cm2 Part (a) Calculate the pressure, in pounds per square inch, exerted on the floor by the heel if it has an area of 1.25 cm2 and the woman As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. This creates quite a large pressure on the ground - in fact, in the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were too thin to withstand such large pressures.

Randomized Variablesm = 51.5 kg
A = 1.25 cm2 Part (a) Calculate the pressure, in pounds per square inch, exerted on the floor by the heel if it has an area of 1.25 cm2 and the woman

Explanation / Answer

Mass of woman m = 51.5 kg

Weight of woman W = mg

                                 = 51.5 x 9.8

                                = 504.7 N

Area A = 1.25 cm 2

           = 1.25 x 10 -4 m 2

Pressure P = W / A
                 = 4.0376 x 10 6 N / m 2

                = 4.0376x 10 6 Pa

We know

1 pound per square inch = 6895 pascals

P = (4.0376x 10 6) /6895 pounds per square inch

   = 585.5 pound per square inch

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