A rectangular wire loop with a cross-sectional area of 0.20 m2 carries current o

Question

A rectangular wire loop with a cross-sectional area of 0.20 m2 carries current of 0.25 A. The loop is free to rotate about an axis that is perpendicular to a uniform magnetic field with strength 0.30 T. The plane of the loop is at an angle of 30o to the direction of the magnetic field. (a) What is the magnitude of the torque on the loop? (b) How would you change the magnetic field to double the magnitude of the torque in part (a)? (c) Could you double the torque in part (a) only by changing the angle? Explain. If so, find that angle.

Explanation / Answer

? = NIAB sin ? ;

? = IAB sin ? ;

? = 0.25 * 0.2 * 0.3 sin ( 90 - 30 ) ;

? = 0.012990 N. m <---------ans

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