On a frictionless horizontal air table, puck A (with mass 0.250kg ) is moving to

Question

On a frictionless horizontal air table, puck A (with mass 0.250kg ) is moving toward puck B (with mass 0.365kg ), which is initially at rest. After the collision, puck A has velocity 0.118m/s to the left, and puck B has velocity 0.653m/s to the right.

Part A

What was the speed vAi of puck A before the collision?

SubmitHintsMy AnswersGive UpReview Part

Part B

Calculate ?K , the change in the total kinetic energy of the system that occurs during the collision.

On a frictionless horizontal air table, puck A (with mass 0.250kg ) is moving toward puck B (with mass 0.365kg ), which is initially at rest. After the collision, puck A has velocity 0.118m/s to the left, and puck B has velocity 0.653m/s to the right.

Part A

What was the speed vAi of puck A before the collision?

SubmitHintsMy AnswersGive UpReview Part

Part B

Calculate ?K , the change in the total kinetic energy of the system that occurs during the collision.

vAi = m/s

Explanation / Answer

befor collision

initial momentum Pi = mA*VAi + mB*vBi

B is at rest vBi = 0

Pi = mA*vAi

after collision

vAf = -0.118 m/s

vBf = 0.653 m/s

final momentum Pf = mA*vAf + mB*vBf

for any collision from law of conservation of momentum

initial momentum = final momentum

pf = Pi

mA*vAf + mB*vBf = mA*vAi

0-(0.25*0.118) + (0.365*0.653) = (0.25*vAi

vAi = +0.835 m/s towards B

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.