The diagram represents a snapshot of a standing transverse wave on a flexible st

Question

The diagram represents a snapshot of a standing transverse wave on a flexible string taken when the displacement is at a maximum. The string is 1.28 m long with tension 5.00 N. The total mass of the string is 7.09 g.

Find the period of the oscillation.

Please Help!

The diagram represents a snapshot of a standing transverse wave on a flexible string taken when the displacement is at a maximum. The string is 1.28 m long with tension 5.00 N. The total mass of the string is 7.09 g.

Find the period of the oscillation.

Please Help!

Explanation / Answer

since the diagram is not visible so,

let there are n waves so

? = L / n

? = 1.28 / n

The speed of propagation of a wave in a string (v) is proportional to the square root of the tension of the string (T) and inversely proportional to the square root of the linear mass (?) of the string:

v = sqrt(?/?)

also

f = v/?

so,

f = sqrt(?/?) / ?

f = sqrt(5 / (0.007 / 1.28)) / (1.28 / n )

period ? = 1 / f

period = (1.28 / n ) / 30.2372

time period = 0.042332 / n (put the value of n according to the diagram)

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