A 3.00kg mass is hung from a vertical spring causing It to stretch 20.0 cm, The

Question

A 3.00kg mass is hung from a vertical spring causing It to stretch 20.0 cm, The Spring is placed on a frictionless horizontal table. One end Is held Fixed and the other is attached to a 2.00 kg mass. The 2.00 kg mass is then displaced 5.00cm from the equilibrium position and released. Give an equation that Will describe the location of the 2.00kg mass as a function of time. Use a one dimensional coordinate system with its origin located at the equilibrium position of the spring, with the initial displacement in a positive sense.

Explanation / Answer

As

k x = m g

Then

k = m g / x = 147 N/m

Thus, as

x = A cos wt

and A = 5.00 cm, w = sqrt(k/m) = 7.00 rad/s,

x = 5.00 cos (7.00t) cm   [ANSWER]

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