D 4 93% lun 4 mag 10:31 AM Q E Edit Firefox Bookmarks History Bookmarks Tools Wi
ID: 1389505 • Letter: D
Question
D 4 93% lun 4 mag 10:31 AM Q E Edit Firefox Bookmarks History Bookmarks Tools Window Help History O O O Moodle server (for homew x m Homework 17 Multiple x http t...21040 10.html x c Chegg.com C a Search 3 moodle poodle.com mod/quiz/attempt.php?attemp 15481 Most Visited Getting started UowL CHEM user D Disney E ESPN Yahoo! Keepvid: Downlo Apple Yahoo! Google Maps YouTube Notizie Answer: Question 2 V1 9.0 V, V. 24.0 V, R1 18.00, R. 52.0 Q. What is rate of heat release from the 52.00 resistor? Not yet answered Marked out of 1.00 P Flag question Answer: Question 3 V1 3.0 V, V2 18.0 V, R 8.00, R2 21.0 m. What is the voltage drop across the 21.0 resistor? Not yet answered Marked out of 1.00 P Flag question Answer:Explanation / Answer
The equivalent value of battery emf is V=V1+V2=33 V
The equivalent value of resistance is R=R1+R2= 70 Ohm
Thus, the current in the circuit is i=V/R=33/70= 0.47 A.
The rate of heat that dissipated through 52 Ohm is
P=i^2R=(0.47)2(52)=11.6 W
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.