A solenoid (figure B) has a radius 0.125 meters, length 1.8 meters, and 600 turn
ID: 1390579 • Letter: A
Question
A solenoid (figure B) has a radius 0.125 meters, length 1.8 meters, and 600 turns of wire. If the current in the solenoid is 35 amps, calc the magnitude of the magnetic field in the solenoid.
Referring to the solenoid in figure B, the current is clockwise when viewed from the left. Assume a positive charge is located in the middle of the solenoid with a velocity direction up toward the top of the page. At this moment, determine the direction of magnetic force acting on the positive charge.
The other answer on chegg may be wrong. This is my second time posting the same question. Please show work to justify the answer. Thank you very much.
Explanation / Answer
Here ,
magnitude of magnetic field , B = u0*N*I/L
B = u0*600 * 35/1.8
B = 0.0147 T
the magnitude of magnetic field is 0.0147 T
Here , as the current is clockwise from left ,
magnetic field is to the right ,
velocity of particcle is upwards ,
as F = q V X B
the direction of magnetic force is INTO THE PAGE
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.