The cornea of the eye has a radius of curvature of approximately 0.500cm , and t

Question

The cornea of the eye has a radius of curvature of approximately 0.500cm , and the aqueous humor behind it has an index of refraction of 1.35. The thickness of the cornea itself is small enough that we shall neglect it. The depth of a typical human eye is around 2.31cm

I got A and B but for some reason numbers are not working for C

A) What would have to be the radius of curvature of the cornea so that it alone would focus the image of a distant mountain on the retina, which is at the back of the eye opposite the cornea?
Answer: .599 cm

B)If the cornea focused the mountain correctly on the retina as described in part A, where would it focus the text from a computer screen if that screen were 26.4cm in front of the eye?
Answer: 2.47 cm

C)Given that the cornea has a radius of curvature of about 0.480cm , where does it actually focus the mountain?

Explanation / Answer

The lens makers foumula is

    n1 / p+ n2 / q = n2 - n1 / R

        1/ 26.4 cm + 1.35/q = 1.35 - 1/ 0.480 cm

               q = 1.95 cm

    1/ 26.6 cm + 1.35 / d_i = 1.35 - 1 / 0.450cm

       d_i = 1.82 cm

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