I am doing the calculations for a lab report on circuits, but I\'m not sure how

Question

I am doing the calculations for a lab report on circuits, but I'm not sure how to take the data I have and turn it into the proper calculations I need. If you could check out the relavent data I post below and show me how to set up or do the calculations, I would be most appreciative!

From the lab walk through:

Parallel Capacitors

Use the round bulb and two batteries again, but connect two identical capacitors together in parallel instead. Again charge the capacitors and measure the final voltages across each once fully charged.

Try it again using one silver and one green capacitor. Be sure to check the voltage across each capacitor when you are finished.

1. Calculate the equivalent capacitance of this circuit and use the known capacitances of each capacitor to calculate what final voltage each should have for each situation. Compare the theoretical and measured values of voltage for each.

Here is the data that my team

Silver capacitor: measured initially 2.641V. The light went out at 50 seconds and we measured the voltage at 0.130V. At 1min 40sec the voltage was 0.012V

Green capacitor: measured initially 2.644V. Not sure when the light went out, but at 1min 40sec it measured 0.005V.

Any help you can give would be most appreciated!

edit: for those wondering, battery A = 1.327 V and battery B = 1.326 V. The capacitance value for the silver one was 0.1F, and the green capacitor was 1F.

Explanation / Answer

Pls check the question again,

You have provided the intial voltage of silver and the drop in the next statement, but did not mention the time.

Secondly provide the corresponsing capacitance values of silver and green capacitors, as indicated over them or specifications card.

Let Cs be the capacitance of silver and Cg be that of green.We know that the equivalent capacitance is calculated as follows:

For parallel Simply, C(eq) = Cs + Cg

For series C(eq) = Cs x Cg / (Cs + Cg)

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