a simple pendulum with a point mass at the end extends from a ceiling to the flo

Question

a simple pendulum with a point mass at the end extends from a ceiling to the floor and has a period of 3.0 s. (A)what is the height of the room? (B)you take the same pendulum to the top floor of a building and measure the period T = 3.0002s. what is the height of the building? a simple pendulum with a point mass at the end extends from a ceiling to the floor and has a period of 3.0 s. (A)what is the height of the room? (B)you take the same pendulum to the top floor of a building and measure the period T = 3.0002s. what is the height of the building?

Explanation / Answer

in SMH , the time period T = 2*pi*sqrt(L/g)

L = length of the pendulum = height of the room = H

g = acceleration due to gravity = 9.8

T = tome period = time tsken for one oscillation = 3 s

L = T^2*g/(4*pi^2)

H = (3^2*9.8)/(4*3.14^2)

H = 2.24 m

----------------

B)

g = (4*pi^2*L)/T'^2

g = (4*3.14^2*2.24)/(3.0002^2)

g = 9.8145

g = GM/(R+H)^2

(R+H)^2 = GM/g

(R+H) = sqrt(GM/g)

R+H = sqrt((6.67384*10^-11*5.97219*10^24)/9.8145)

R+H = 6372658.0246 m

H = 6372658.0246-r = 6372658.0246-6371000 = 1658.0246 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.