The mass of the cherry picker is 700 kg and the centre of this mass is located a
ID: 1392860 • Letter: T
Question
The mass of the cherry picker is 700 kg and the centre of this mass is located at point ?G?. A worker plus equipment has a mass of 250 kg and the centre of this mass is located at point ?G1? as shown in the figure. Axle ?A? has a brake that prevents rolling and axle ?B? is free to rotate.
For the system as shown, calculate the reaction forces that the ground exerts onto to cherry picker at ?A? and ?B?. For the geometry as shown, calculate combined mass of the worker plus equipment that will make the cherry picker be at the point of overturning. (Hint: this will occur at the instant when the wheel load at point ?B? goes to zero).
Explanation / Answer
weight of worker plug equipment = Fw = 250 x g = 2450 N
weight of cherry picker = Fc = 700 x g = 6860 N
taking equilibrium of torque about point A ::
Fc (2.4) - Fb (3.4) - Fw (4.5 - 2.4 - 1) =0
(6860) (2.4) - Fb (3.4) - (2450) (1.1) = 0
Fb = 4049.71
from equilibrium of forces :
Fa + Fb = Fw + Fc
Fa + 4049.71 = 16464 + 2450
Fa = 14864.29 N
let the combined mass be ''m''
taking equilibrium of torque at point ''G''
Fa x 2.4 = mg (4.5 - 1)
14864.29 x 2.4 = m x 9.8 x 3.5
m = 1040.1 N
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