IP The point charges in the figure(Figure 1) have the following values: q1 = 2.0

Question

IP The point charges in the figure(Figure 1) have the following values: q1 = 2.0?C , q2 = 6.4?C , q3 = -0.88?C .

Part A

Given that the distance d in the figure is 4.13cm , find the direction and magnitude of the net electrostatic force exerted on the point charge q1.

Express your answer using two significant figures.

Part B

Express your answer using three significant figures.

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Part C

How would your answer to part A change if the distance d were doubled?

How would your answer to part A change if the distance were doubled?

Explanation / Answer

q1 = 2.0 x 10-6 C

q2 = 6.4 x 10-6 C

q3 = -0.88 x 10-6 C

d = 0.0413 m

A)

F3 = kq1q3/d2 along +ve x axis

F3 = 9 x 109x 2.0 x 10-6 x 0.88 x 10-6 / 0.04132

F3 = 9.29 N

__

F2 = -kq1q2/d2

F2  = 9 x 109x 2.0 x 10-6 x 6.4 x 10-6 / 0.04132

F2 = 67.53 N

__

X component of F2

F2x = -F2cos60

F2x = - 33.76 N

Y component of F2

F2y = -F2sin60

F2y = -58.48

__
X xomponent of net force

Fx = F3 + F4x

Fx = 9.29 - 33.76

FX = -24.47 N

Y xomponent of net force

FY = F4Y

FY = -58.48 N

__

Totoal Force

F = (Fx2 + Fy2)

F = {(-24.472 )+ (-58.482)}

F = 63 N

B)

Direction

= arctan(Fy/Fx)

= arctan(-58.48/-24.47)

= 67o from -ve x axis

= 247o from q1-q3 direction

C)

Force is inversly proportional to the square of the distance d

Increasing d by a factor of 2 would decrease the forc by a factor of 4

So answer is

Decreased by a factor of 4

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